[UW-GIS-L] Best projection for measuring distances
across theWestern Hemisphere?
Phil Hurvitz
phurvitz at uw.edu
Thu Oct 21 23:33:08 PDT 2010
Hi Tristan, you might consider PostGIS, which supposedly calculates
great circle distances. This is a good synopsis:
http://workshops.opengeo.org/postgis-intro/geography.html
-P.
**************************************************************
Phil Hurvitz, MFR | PhD Student, Urban Planning | CBE
1107 NE 45th Street, Suite 535 | Box 354802
University of Washington, Seattle, Washington 98195-4802, USA
phurvitz at u.washington.edu | http://gis.washington.edu/phurvitz
"What is essential is invisible to the eye." -de Saint-Exupéry
**************************************************************
On 10/21/2010 10:55 PM, Jin-Kyu Jung wrote:
> I think It should be one of equal-distance projections. In ArcGIS, Azimuthal Equidistant, Equidistant Conic or Equidistant Cylindrical can be a good option. I am a little bit surprised that ESRI help site suggested conformal, equal area (e.g. sinusoidal) or even compromised Robinson projection to measure an accurate distance, though. Please, someone correct me if I am wrong. Thank you!
>
> Jin-Kyu Jung
>
> On Oct 21, 2010, at 10:30 PM, Keven Bennett wrote:
>
>> World Robinson is the best I know of.
>>
>> Keven
>>
>> -----Original Message-----
>> From: uw-gis-l-bounces at mailman1.u.washington.edu
>> [mailto:uw-gis-l-bounces at mailman1.u.washington.edu] On Behalf Of Tristan
>> Nunez
>> Sent: Thursday, October 21, 2010 8:58 PM
>> To: uw-gis-l at u.washington.edu
>> Subject: [UW-GIS-L] Best projection for measuring distances across
>> theWestern Hemisphere?
>>
>> Hi GIS folks,
>>
>> Do you have any suggestions on the best projection to use to measure
>> distances in km (using the Euclidean distance tool in Arc 9.3) ranging
>> from 0 km to 1000 km, across the Western Hemisphere? The map is
>> currently in GCS_WGS_1984.
>>
>> Sources on the web and in ESRI's help site suggest that the Bipolar
>> Oblique Conformal Conic projection was useful for this purpose, but
>> ArcMap 9.3 doesn't have it in its coordinate systems library. From the
>> ArcMap 9.3 help files, it seems like a sinusoidal projection centered
>> at 90 W, a Robinson projection, or doing North and South America
>> separately in a Lambert Conformal Conic projection would be the best
>> compromise.
>>
>> Any thoughts would be highly welcome.
>>
>> Many thanks,
>>
>> Tristan
>>
>> --
>> Tristan Nuñez
>> Master of Science Candidate
>> Landscape Ecology and Conservation Lab
>> University of Washington
>> tristan.nunez at gmail.com
>> c. 503-819-5884
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